Packet Tracer Labs

# Class C Subnetting

Available Subnet - 215.37.1.0/24

Required subnets – 25

Process

/24 = 255.255.255.0 = 11111111.11111111.11111111.00000000  All ones represents the network       zeroes represents the hosts

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Find an increment

2^n = subnets (n = numbers of bits required)

To find out required bits, multiply 2x2 until you get required subnets number or bigger number

In this scenario we need 25 subnets and we are getting number 32 by
2x2x2x2x2 = 32,

2^5 = 32 subnets

We need to convert five bits to get 25 subnets

We have to change hosts bits into network bits to get more subnets

11111111.11111111.11111111. 11111000
8              8                8               5 Five hosts bits are now network bits

Count all the ones to get new subnet mask

Our new subnet mask is /29 = 255.255.255.11111000 128+64+32+16+8=248

= 255.255.255.248

128   64   32   16   8   4   2   1

1      1     1        1   0   0   0        8 is the smallest network bit We will find our network ranges using 8 as a increment

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Network ranges

215.37.1.0------------------      215.37.1.7
+8 (Increment)

215.37.1.8------------------      215.37.1.15
+8

215.37.1.16-----------------    215.37.1.31
+8

215.37.1.32-----------------    215.37.1.39
+8

215.37.1.40-----------------    215.37.1.47
+8

215.37.1.48-----------------    215.37.1.55
+8

215.37.1.56-----------------    215.37.1.63
+8

215.37.1.64-----------------     215.37.1.71 and so on

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